Recoil energy generated when you shoot a shotgun is calculated in foot-pounds. You need to know the load weight in ounces, the muzzle velocity, (i.e. 1 1/8th ounce at 1145 fps) and the weight of the gun in pounds. If you know the weight of the wad and the number of grains of powder, you can also enter those numbers, otherwise average values of 33 grains for the wad and 18 grains for the powder will be used. The weight of the wad and powder do not typically change the result by a significant amount.
All numbers must be entered as decimal values.
|Common target loads||Other loads|
|24 gram = 0.847 oz.||1 1/4 oz. = 1.25 oz.|
|7/8 oz. = 0.875 oz.||1 5/8 oz. = 1.675 oz.|
|1 1/8 oz. = 1.125 oz.||1 7/8 oz. = 1.875 oz.|
|00-Buck 8-pellet = 0.984 oz.||00-Buck 9-pellet = 1.107 oz.|
The three primary variables that influence recoil energy are the amount of shot that goes out the barrel, the velocity of the shot and the weight of the gun. Increase the amount of shot or the velocity of the shot and the recoil energy increases. Increase the weight of the gun and the recoil energy decreases.
There are two basic physics principles involved in this problem ... conservation of momentum and calculation of kinetic energy. Complicating the issue is that we use ounces for shot weight, grains for powder weight, lots of different units for wad weight and physics likes mass not weight.
Before you shoot a shotgun the gun and the shot shell pellets are both at rest. After you shoot the pellets/wad/powder goes out the barrel and the gun goes in the other direction. The key here is momentum which is mass times velocity. So although the velocity of the pellets is large, their mass is small compared to the mass of the gun. The key equation here is:
mgunvgun=mshotvshot + mwadvwad + mpowdervpowder
Where the left side is the mass and velocity of the gun and the right is the mass and velocity of the shot pellets, wad and powder gases. The velocity of the shot and wad is given to us by the manufacturers. The velocity of the powder gases is a little more complicated. There are a number of values for the velocity of the gases. The most commonly used one is 4,700 ft/s. Another estimate is 1.7 times the muzzle velocity of the shot. For this calculator I am using 4,700 ft/s. The difference here is one of a few percent, not very significant.
Since we know the mass/weight of the shot, the mass of the powder, the muzzle velocity and the mass/weight of the gun we can calculate the recoil velocity of the gun.
Once we have the recoil velocity of the shotgun we can calculate the kinetic energy of the gun. This is the "free" recoil energy. The recoil energy is calculated as:
Energy = 1/2 mgunvgun2
So we now have all we need to calculate the recoil energy of a shotgun if we know the weight of the gun, the amount of shot, the velocity of the shot, the weight of the wad and the amount of powder. If you don't know the weight of the wad or the weight of the powder I put in average values. No worries as these two values won't change the final answer by a significant amount.
The other problem is to do a bunch of conversions. There are 16 ounces to a pound and 7,000 grains to a pound. Getting from weight to mass requires that we convert pounds to slugs ... on earth there are about 32 lbs to a slug.
So the final equation for calculating recoil energy is:
Recoil Energy = (mshotvshot + mwadvwad + 4,700 * mpowder) 2/64.348* mgun
where in the numerator we have the mass of the shot times the velocity of the shot plus the mass of the wad times the velocity of the wad plus the velocity of the powder (4,700 ft/s) times the mass of the powder. That quantity is squared. It is divided by the mass of the gun. The 64.348 does all of the conversions (lbs to slugs*2 for kinetic energy).
The Meaning of Drams Equivalent
Probably one of the most confusing aspects of understanding shotshells is this business of drams equivalent. This designation goes back to the early days when smokeless powder was first being loaded in shotshells, and black powder loads were the norm. A dram is 1/16 of an ounce or 27.34 grains, and 12 gauge black powder field loads in the late 19th century quite typically contained 3-3/4 drams of black powder behind 1-1/4 ounces of shot. You cannot load the same weight of smokeless powder into a shotshell and expect to survive the experience, so the drams equivalent designation was invented in order for shotgunners of the day, who were familiar with black powder loadings, to have a basis of comparison between typical black powder loads and the new smokeless powder loads. Drams equivalent is therefore related to the velocity produced by smokeless powder for a given black powder charge in drams and varies by gauge and the weight of shot. For example, a typical 12 gauge 1-1/8 ounce shot load that is 3 drams equivalent will produce a nominal 1200 fps at the muzzle, but a 20 gauge 7/8 ounce load to produce about the same muzzle velocity is a 2-1/2 drams equivalent load. The following is a table that correlates the drams equivalent loads by gauge, shotshell length, shot weight, and muzzle velocity.
|Gauge||Case Length (inches)||Shot Weight (ounces)||Drams Equivalent||Nominal Velocity (fps)|
Interesting 12 Gauge Recoil Comparisons
|SKU||Description||Velocity (fps)||Recoil Energy (ft-lbs)|
|LEF127RS||FED LE 1 oz Slug||1600||27.8|
|LE127RS||FED LE 1 oz Slug||1300||19.2|
|CMSLUG||RWS Copper Matrix 7/8 oz Slug||1404||17.1|
|12LESLUG||Fiocchi 3-Gun 7/8 oz Slug||1300||15.5|
|LE12700||FED LE 9-pellet 00-Buck||1325||23.6|
|LE13200||FED LE 9-pellet 00-Buck||1145||18.2|
|LE13300||FED LE 8-pellet 00-Buck||1145||15.4|
|XU12H4||WIN 1-1/8 oz #4||1255||21.9|
|XU126||WIN 1 oz #6||1290||19.0|
|TLT288||RIO 1 oz #8 Target||1210||17.0|
|SP410RS||REM 1/5 oz Slug||1830||4.9|
Original Information: http://www.reloadingpro.com & https://www.marianhighschool.net/